GCSE Chemistry (AQA)

196 videos | 19 hours

Titration Calculations

Please subscribe to watch this video.

This, and all other videos, are included in our premium subscriptions.

Premium accounts get access to all videos.

Chemical changes Reactions of acids

Titration Calculations

12:30 Acid-Base Titrations
Spec 4.4.2.5
Previous Titration Next Half Equations
  • Titration results can determine the unknown concentration of a solution.
  • Concentration in moles per decimeter cubed is calculated using: amount of solute in moles divided by volume in decimeters cubed.
  • Formula triangle: C (concentration), N (number of moles), V (volume).
  • Example titration: 28.5 cm�� of 1.0 mol/dm�� nitric acid neutralized by 25.0 cm�� of sodium carbonate.
  • Precise measurements lead to precise concentration calculations.
  • Reaction: 2 moles of nitric acid react with 1 mole of sodium carbonate.
  • Calculate moles of known reactant (nitric acid) using the formula triangle.
  • Convert volumes from cm�� to dm�� by dividing by 1000.
  • Use the formula triangle to find the amount of solute (N) by multiplying concentration (C) and volume (V).
  • Calculate moles of sodium carbonate using the ratio from the balanced equation.
  • Calculate unknown concentration using the formula triangle: N divided by V.
  • Convert concentration from moles/dm�� to grams/dm�� using relative formula mass.
  • Example: Convert concentration of sodium carbonate to grams/dm�� using its relative formula mass (106).
  • Another example: Calculate concentration of sodium hydroxide in grams/dm�� from titration with hydrochloric acid.
  • Steps: List values, convert units, calculate moles, use reactant ratio, calculate unknown concentration, convert to grams/dm��.
  • Use periodic table to find relative formula mass for conversions.

Please subscribe to access these revision notes.

This, and all other video notes, are included in our premium subscriptions.

Premium accounts get access to all videos and revision notes.