GCSE Combined Science (AQA)
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Electrical Power
- Power output of an electrical component depends on current and potential difference.
- Power is the rate of energy conversion from charge carriers into other forms.
- Power is determined by energy given by a charge carrier and frequency of passage through the component.
- Power equation: P = I x V (Power = Current x Potential Difference).
- Current is measured in amps, potential difference in volts, and power in watts.
- Example: Microwave with power output of 1200 watts and potential difference of 240 volts; calculate current.
- Power ratings indicate safe range of potential difference and power for components.
- To calculate current: Rearrange power equation to I = P / V.
- Substitute values: Current = 1200 watts / 240 volts = 5 amps.
- Increase power output by increasing current or potential difference.
- Example: Increase bulb brightness by adding a cell or removing a resistor.
- Adding a cell increases potential difference; removing a resistor decreases resistance and increases current.
- Use resistors to prevent current from becoming too high.
- Power increases with increased potential difference and current.
- For exams, explain how changing potential difference, current, or resistance affects power.
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