GCSE Physics (AQA)

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Alpha Decay Equations

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Atomic structure Atoms and nuclear radiation

Alpha Decay Equations

3:09 Decay Equations
Spec 4.4.2.2
  • Alpha decay involves a nucleus losing two protons and two neutrons.
  • Nuclei that undergo alpha decay are typically too large to remain stable.
  • The emitted alpha particle consists of two protons and two neutrons bound together.
  • Post-decay, the nucleus becomes smaller and more stable due to its reduced size.
  • The mass number of the nucleus decreases by four and the atomic number decreases by two after alpha decay.
  • Atomic notation includes the mass number (A) representing total neutrons and protons, and the atomic number (Z) representing just the protons.
  • The element symbol (X) identifies the element.
  • A nuclear equation for alpha decay can be written, showing changes in A and Z, similar to a chemical equation.
  • The alpha particle is represented as a helium nucleus in the equation.
  • The new nucleus (Y) is a different element due to the change in proton number.
  • The new mass number is calculated by subtracting four from the original, and the new atomic number by subtracting two.
  • The equation's correctness is verified by ensuring the total A and Z values are consistent on both sides.
  • The new atomic number helps identify the new element resulting from the decay.
  • The new nucleus may undergo further decays to reach stability.
  • Example given: Polonium-210 (Po) with 84 protons and 126 neutrons undergoes alpha decay to become Lead-206 (Pb) with 82 protons.
  • Steps to write the nuclear equation include adjusting the atomic and mass numbers and identifying the resulting element.

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